Question

java中怎么获取客户端的真实的IP-CSDN论坛

Answer 1

1.直接用jdk方法
InetAddress address = InetAddress.getLocalHost();
String IP=address.getHostAddress();
2.用request获取
public static String getRemoteIpAddr() {
HttpServletRequest request = getRequest();
String ip = request.getHeader("x-forwarded-for");
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return ip;
}

public static HttpSession getSession() {
return getRequest().getSession();
}
public static HttpServletRequest getRequest() {
return ServletActionContext.getRequest();
}

Answer 2

private String getIpAddr() {
String ipAddress = null;
//ipAddress = this.getRequest().getRemoteAddr();
ipAddress = this.getRequest().getHeader("x-forwarded-for");
if(ipAddress == null || ipAddress.length() == 0 || "unknown".equalsIgnoreCase(ipAddress)) {
ipAddress = this.getRequest().getHeader("Proxy-Client-IP");
}
if(ipAddress == null || ipAddress.length() == 0 || "unknown".equalsIgnoreCase(ipAddress)) {
ipAddress = this.getRequest().getHeader("WL-Proxy-Client-IP");
}
if(ipAddress == null || ipAddress.length() == 0 || "unknown".equalsIgnoreCase(ipAddress)) {
ipAddress = this.getRequest().getRemoteAddr();
if(ipAddress.equals("127.0.0.1")){
//根据网卡取本机配置的IP
InetAddress inet=null;
try {
inet = InetAddress.getLocalHost();
} catch (UnknownHostException e) {
e.printStackTrace();
}
ipAddress= inet.getHostAddress();
}

}

//对于通过多个代理的情况，第一个IP为客户端真实IP,多个IP按照','分割
if(ipAddress!=null && ipAddress.length()>15){ //"***.***.***.***".length() = 15
if(ipAddress.indexOf(",")>0){
ipAddress = ipAddress.substring(0,ipAddress.indexOf(","));
}
}
return ipAddress;
}