Question

main() { int a=1,*p,**pp; pp=&p; p=&a; a++; printf("%d,%d\n",a,*p,**pp); } 求输出结果，详细解及思路

main()
{ int a=1,*p,**pp;
pp=&p;
p=&a;
a++;
printf("%d,%d\n",a,*p,**pp);
}
求输出结果，详细解及思路

Answer 1

a++ => a = a+1 => a=2

p=&a => *p = 2

pp=&p => *(*pp) = *p =2