Question

网页中如何读取天气预报返回的json数据

网页中如何读取http://m.weather.com.cn/data/101010100.html 页面的json数据

Answer 1

代理的代码，用的是雅虎的代理：

 $(document).ready(function() {  
        //  天气  
        $.getJSON("http://query.yahooapis.com/v1/public/yql", {  
                q: "select * from json where url=\"http://m.weather.com.cn/atad/101190101.html\"",  
                format: "json"  
                }, function(data) {  
                var $content = $("#content")  
                if (data.query.results) {  
                var weatherinfo = data.query.results.weatherinfo;     
                //console.log(weatherinfo);  
                  var week = ["星期一","星期二","星期三","星期四","星期五","星期六","星期天","星期一","星期二"];  
                  var week_tomorrow ="";  
                  var week_tdat ="";  
                  var week_today = weatherinfo.week;  
                  var index = $.inArray(week_today,week);  
                  week_tomorrow = week[index+1];  
                  week_tdat = week[index+2];  
                  $(".today .location").text(weatherinfo.city);    
} else {  
                    $(".today p:eq(1)").text("获取数据失败");     
                }  
              });

Answer 2

var msg="";//JSON数据        
var jnone = [];
eval("jnone=" + msg);
alert(jnone.weatherinfo); //直接点属性就可以了。

Answer 3

jquery:

$.getJSON('http://m.weather.com.cn/data/101010100.html', function(data) {
    //data为获取的天气对象
});

追问

获取不到数据额，我要的是这种

<script type="text/javascript">

   var wjson={"weatherinfo":{获取的JSON数据 }}

</script>

追答

返回的对象直接用weatherinfo属性取就可以了....

追问

追答

var jsonObj=eval(wjson);

//or
var jsonObj1=JSON.Parse(wjson);