Question

Java服务器怎么接收手机上传过来的文件。求具体代码，谢谢，如果觉得悬赏太少的话可以说，我再加。急。。

Answer 1

android客户端代码:
public class MainActivity extends Activity
{
private TextView uploadInfo;

@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

uploadInfo = (TextView) findViewById(R.id.upload_info);

uploadFile();
}

public void uploadFile()
{
//服务器端地址
String url = "http://192.168.0.108:8080/UploadFileServer/upload";
//手机端要上传的文件，首先要保存你手机上存在该文件
String filePath = Environment.getExternalStorageDirectory()
+ "/1/power.apk";

AsyncHttpClient httpClient = new AsyncHttpClient();

RequestParams param = new RequestParams();
try
{
param.put("file", new File(filePath));
param.put("content", "liucanwen");

httpClient.post(url, param, new AsyncHttpResponseHandler()
{
@Override
public void onStart()
{
super.onStart();

uploadInfo.setText("正在上传...");
}

@Override
public void onSuccess(String arg0)
{
super.onSuccess(arg0);

Log.i("ck", "success>" + arg0);

if(arg0.equals("success"))
{
Toast.makeText(MainActivity.this, "上传成功！", 1000).show();
}

uploadInfo.setText(arg0);
}

@Override
public void onFailure(Throwable arg0, String arg1)
{
super.onFailure(arg0, arg1);

uploadInfo.setText("上传失败！");
}
});

} catch (FileNotFoundException e)
{
e.printStackTrace();
Toast.makeText(MainActivity.this, "上传文件不存在！", 1000).show();
}
}
}
服务器端代码：
public class UploadFileServlet extends HttpServlet
{

public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
response.setContentType("text/html");
PrintWriter out = response.getWriter();

// 创建文件项目工厂对象
DiskFileItemFactory factory = new DiskFileItemFactory();

// 设置文件上传路径
String upload = this.getServletContext().getRealPath("/upload/");
// 获取系统默认的临时文件保存路径，该路径为Tomcat根目录下的temp文件夹
String temp = System.getProperty("java.io.tmpdir");
// 设置缓冲区大小为 5M
factory.setSizeThreshold(1024 * 1024 * 5);
// 设置临时文件夹为temp
factory.setRepository(new File(temp));
// 用工厂实例化上传组件,ServletFileUpload 用来解析文件上传请求
ServletFileUpload servletFileUpload = new ServletFileUpload(factory);

// 解析结果放在List中
try
{
List<FileItem> list = servletFileUpload.parseRequest(request);

for (FileItem item : list)
{
String name = item.getFieldName();
InputStream is = item.getInputStream();

if (name.contains("content"))
{
System.out.println(inputStream2String(is));
} else if(name.contains("file"))
{
try
{
inputStream2File(is, upload + "\\" + item.getName());
} catch (Exception e)
{
e.printStackTrace();
}
}
}

out.write("success");
} catch (FileUploadException e)
{
e.printStackTrace();
out.write("failure");
}

out.flush();
out.close();
}

// 流转化成字符串
public static String inputStream2String(InputStream is) throws IOException
{
ByteArrayOutputStream baos = new ByteArrayOutputStream();
int i = -1;
while ((i = is.read()) != -1)
{
baos.write(i);
}
return baos.toString();
}

// 流转化成文件
public static void inputStream2File(InputStream is, String savePath)
throws Exception
{
System.out.println("文件保存路径为:" + savePath);
File file = new File(savePath);
InputStream inputSteam = is;
BufferedInputStream fis = new BufferedInputStream(inputSteam);
FileOutputStream fos = new FileOutputStream(file);
int f;
while ((f = fis.read()) != -1)
{
fos.write(f);
}
fos.flush();
fos.close();
fis.close();
inputSteam.close();

}

}

追问

谢谢。
手机上传过来的东东是在哪个变量里面的。这个方法我有在网上找到，就是不知道要怎么用，看起来怎么觉得没有一个变量是跟客户端打交道了。
IOS的要怎么用

追答

首先你得在客户端选中一个文件把，apk iph啥的 然后点击“上传” 就请求了String url = "http://192.168.0.108:8080/UploadFileServer/upload"; 一个url对吧 然后就以流的方式把文件传输过去，你再用spring 类似这段代码 “@RequestMapping("/uploadPage")
@ResponseBody
public String uploadPage(Long id,@RequestParam("userfile") CommonsMultipartFile mFile){”，接下来就是里边具体内容的处理了，上面的例子是普通的servlet。如果用spring框架就套用这个。

追问

谢谢！
我有用Spring框架，不过还不是很明白你说的，能不能再说详细一点，还有这几个注解要导入什么包。Spring学的不是很多

我查过了，网上说是Struts2的过滤器过滤没了，所以List list = servletFileUpload.parseRequest(request);一直为空。然后把/*改成*.action就又报错了

追答

哦 我用的这是spring mvc struts2用的太早了，不记得了。反正中心思想就是提交流媒体到java服务端，能获得二进制流就行 剩下的就是你怎么运用框架了，具体你查查struts2的上传如何使用。

Answer 2

ftp做，java不用写代码，让手机去写