Question

要详细过程，谢谢！给好评！

Answer 1

解：∵CD平分ad∠ACB
∴∠ACD=∠DCB=30º
∴∠ACB=∠ACD+∠DCB=30+30=60º
又∵DE∥AC
∴∠ACB=∠2=60

Answer 2

因为DE∥AC，CD平分∠ACB
所以∠1＝∠DCE＝CDE＝30°
∠DEC=180°－∠DCE－∠CDE=180°－30°－30°＝120°
所以∠2＝180°－120°＝60°