Question

谁能帮我解下列的因式分解(过程要清楚,说明所用方法)

a2+3a+2
x2-4x+3
x2+x-6
a,x后面的2是平方

Answer 1

a2+3a+2
=a^2+a+2a+2
=a(a+1)+2(a+1)
=(a+2)(a+1)

x2-4x+3
=x^2-x-3x+3
=x(x-1)-3(x-1)
=(x-3)(x-1)

x2+x-6
=x^2+3x-2x-6
=x(x+3)-2(x+3)
=(x-2)(x+3)