Question

请用算法写出两个有序表合并成一个有序线性表(用C语言

设有两个有序线性单链表，头指针分别为AH与BH。试写出将这两个有序线性单链表合并为一个头指针为CH的有序电信单链表的算法。

Answer 1

#include "stdio.h" main() { int a,b,c,i,j,k,low,high,mid; int la[50]; int lb[50]; int lc[50]; printf("Please input the width of la,lb,lc:\n"); printf("Input here:"); scanf("%d,%d,%d",&a,&b,&c); printf("a=%d,b=%d,c=%d\n",a,b,c); if (a+b>c) printf("lc overflow,operation halt!\n"); else { printf("Input la:"); for(i=1;i<=a;++i) { scanf("%d",&la[i]); la[0]=la[i]; low=1; high=i; while(low<=high) { mid=(low+high)/2; if(la[0]=low;j--) la[j+1]=la[j]; la[low]=la[0]; } printf("\n"); printf("Input lb:"); for(i=1;i<=b;++i) { scanf("%d",&lb[i]); lb[0]=lb[i]; low=1; high=i; while(low<=high) { mid=(low+high)/2; if(lb[0]=low;j--) lb[j+1]=lb[j]; lb[low]=lb[0]; } printf("\n"); printf("la is:"); for (i=1;i<=a;i++) printf("%d ",la[i]); printf("\n"); printf("lb is:"); for (j=1;j<=b;j++) printf("%d ",lb[j]); i=1;j=1;k=0; while (i<=a && j<=b) if (la[i]>lb[j]) { lc[k]=lb[j];k++;j++;} else { lc[k]=la[i];k++;i++;} while (i<=a) {lc[k]=la[i];k++;i++;} while (j<=b) {lc[k]=lb[j];k++;j++;} printf("\n"); printf("lc is:"); for (i=0;i } getch(); } 把la,lb,lc分别换一下就OK了

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