Question

[数学题]分解因式

分解因式:
2x(2x-y)^2-y(y-2x)
求答案以及解答过程,谢谢

Answer 1

2x(2x-y)^2-y(y-2x)

=(2x-y)[2x(2x-y)+y]

=(2x-y)[4x^2-2xy+y]

谢谢

Answer 2

2x(2x-y)^2-y(y-2x)
=2x(2x-y)^2+y(2x-y)
=(2x-y)[2x(2x-y)+y]
=(2x-y)(4x²-2xy+y)

Answer 3

2x(2x-y)^2-y(y-2x)
=2x(y-2x)^2-y(y-2x)
=(y-2x)(2x(y-2x)-Y)=(y-2x)(2XY-4X²-Y)

Answer 4

解：原式=2x(2x-y)^2+y(2x-y)
=(2x-y)[2x(2x-y)+y]
=(2x-y)(4x^2-2xy+y)

Answer 5

2*（4x^2+y^2-4xy)-y^2+2xy
下一步
8x^2+2y^2-8xy-y^2+2xy

Answer 6

原式=（2x-y)[2x(2x-y)+y]=(4x^2-2xy+y)(2x-y)