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R1 =(6V)^2/(6W) = 6Ω
R1 =(6V)^2/(3W) = 12Ω
2灯串接12V电源的电流 I= 12V/(6+12)Ω = 2/3 A
实际功率：
P1 = (I^2)R1 = (2/3)^2 x 6 ≈ 2.7w
P2 = (I^2)R2 = (2/3)^2 x 12 ≈ 5.3w
R1 =(6V)^2/(3W) = 12Ω
2灯串接12V电源的电流 I= 12V/(6+12)Ω = 2/3 A
实际功率：
P1 = (I^2)R1 = (2/3)^2 x 6 ≈ 2.7w
P2 = (I^2)R2 = (2/3)^2 x 12 ≈ 5.3w
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