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（1-x²)(1-y²)+4xy
=1-y²-x²+x²y²+4xy
=2xy-y²-x²+(1+xy)²
=-(x-y)²+(1+xy)²
=48
(xy+x-y+1)(xy-x+y+1)=(xy+1)²-(x-y)²=48
xy+x-y+1=6
∴6（xy-x+y+1）=48
xy-x+y+1=8
=1-y²-x²+x²y²+4xy
=2xy-y²-x²+(1+xy)²
=-(x-y)²+(1+xy)²
=48
(xy+x-y+1)(xy-x+y+1)=(xy+1)²-(x-y)²=48
xy+x-y+1=6
∴6（xy-x+y+1）=48
xy-x+y+1=8
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