vb picturebox控件中可以画曲线吗
3个回答
展开全部
可以的。提示:曲线是点的集合。
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
Dim b As New Bitmap(PictureBox1.Width, PictureBox1.Height)
Dim g As Graphics = Graphics.FromImage(b)
g.Clear(Color.White)
Dim p As New Pen(Color.Black)
p.EndCap = Drawing2D.LineCap.ArrowAnchor
g.DrawLine(p, 30, PictureBox1.Height - 30, 30, 30)
g.DrawLine(p, 30, PictureBox1.Height - 30, PictureBox1.Width - 30, PictureBox1.Height - 30)
Dim i As Integer
Dim bs As New SolidBrush(Color.Green)
Dim po As New Point
po.X = 0
po.Y = PictureBox1.Height - 35
For i = 700 To 1000 Step 50
g.DrawString(i, Me.Font, bs, po.X, po.Y)
g.DrawLine(p, po.X + 28, po.Y + 5, po.X + 30, po.Y + 5)
po.Y -= (PictureBox1.Height - 100) / 6
Next
po.X = 30
po.Y = PictureBox1.Height - 30
For i = 0 To 40 Step 5
g.DrawString(i, Me.Font, bs, po.X, po.Y + 5)
g.DrawLine(p, po.X, po.Y + 2, po.X, po.Y)
po.X += (PictureBox1.Width - 100) / 8
Next
PictureBox1.Image = b
Dim g As Graphics = Graphics.FromImage(b)
g.Clear(Color.White)
Dim p As New Pen(Color.Black)
p.EndCap = Drawing2D.LineCap.ArrowAnchor
g.DrawLine(p, 30, PictureBox1.Height - 30, 30, 30)
g.DrawLine(p, 30, PictureBox1.Height - 30, PictureBox1.Width - 30, PictureBox1.Height - 30)
Dim i As Integer
Dim bs As New SolidBrush(Color.Green)
Dim po As New Point
po.X = 0
po.Y = PictureBox1.Height - 35
For i = 700 To 1000 Step 50
g.DrawString(i, Me.Font, bs, po.X, po.Y)
g.DrawLine(p, po.X + 28, po.Y + 5, po.X + 30, po.Y + 5)
po.Y -= (PictureBox1.Height - 100) / 6
Next
po.X = 30
po.Y = PictureBox1.Height - 30
For i = 0 To 40 Step 5
g.DrawString(i, Me.Font, bs, po.X, po.Y + 5)
g.DrawLine(p, po.X, po.Y + 2, po.X, po.Y)
po.X += (PictureBox1.Width - 100) / 8
Next
PictureBox1.Image = b
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询