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(x^2+1)/[(x+1)^2.(x-1)] ≡ A/(x+1) +B/(x+1)^2 +C/(x-1)
=>
(x^2+1) ≡ A(x+1)(x-1) +B(x-1) +C(x+1)^2
x=-1 => B=-1
coef. of x
-2B+2C =0
2+2C=0
C=-1
coef. of x^2
A+C=1
A-1=1
A=2
(x^2+1)/[(x+1)^2.(x-1)] ≡ 2/(x+1) -1/(x+1)^2 -1/(x-1)
=>
(x^2+1) ≡ A(x+1)(x-1) +B(x-1) +C(x+1)^2
x=-1 => B=-1
coef. of x
-2B+2C =0
2+2C=0
C=-1
coef. of x^2
A+C=1
A-1=1
A=2
(x^2+1)/[(x+1)^2.(x-1)] ≡ 2/(x+1) -1/(x+1)^2 -1/(x-1)
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