Question

Jsp问题求助

程序如下：
loginBoke.jsp：
<%@ page contentType="text/html; charset=gb2312"%>
<form id="form1" method="post" action="loginBoke_do.jsp">
<p><strong>登录我的博客</strong></p>
<table width="300" border="1">
<tr>
<td>用户名：</td>
<td><input type="text" name="pass" /></td>
</tr>
<td>密  码：</td>
<td><input type="password" name="pass" /></td>
</tr>
<tr>
<td colspan="2"><div align="center">
<input type="submit" name="submit" value="提交" />
 
<input type="reset" name="submit2" value="重置" />
</div></td>
</tr>
</table>
</form>

loginBoke_do.jsp：
<%@ page contentType="text/html; charset=gb2312"
import="java.util.Date"%>
<%
String name=request.getParameter("name");
String pass=request.getParameter("pass");
if(!(name.equals("")||pass.equals("")))
{ //如果用户提交的用户名和密码都不空返回true
name=new String(name.getBytes("ISO-8859-1"));//处理中文乱码
%>

<center>
<b>欢迎<%=name %>的到来！</b><br>
您登录的时间为：<%=new Date().toLocaleString() %>
</center>

<%
}else{
%><center>对不起！你没有登录成功！</center><%

}
%>

运行结果：（http://localhost:8080/JSP_Ajax/loginBoke.jsp）
type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException: An exception occurred processing JSP page /loginBoke_do.jsp at line 6

3: <%
4: String name=request.getParameter("name");
5: String pass=request.getParameter("pass");
6: if(!(name.equals("")||pass.equals("")))
7: { //如果用户提交的用户名和密码都不空返回true
8: name=new String(name.getBytes("ISO-8859-1"));//处理中文乱码
9: %>

Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:515)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:426)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)

root cause

java.lang.NullPointerException
org.apache.jsp.loginBoke_005fdo_jsp._jspService(loginBoke_005fdo_jsp.java:59)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:384)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)

note The full stack trace of the root cause is available in the Apache Tomcat/6.0.10 logs.

请各位大侠帮帮忙哦~
呵呵··很感谢大家的帮助··用户名那个确实写错了··可是还是出现错误··而且提示是loginBoke_do.jsp文件里的错误··exception

org.apache.jasper.JasperException: An exception occurred processing JSP page /loginBoke_do.jsp at line 6

3: <%
4: String name=request.getParameter("name");
5: String pass=request.getParameter("pass");
6: if(!(name.equals("")||pass.equals("")))
7: { //如果用户提交的用户名和密码都不空返回true
8: name=new String(name.getBytes("ISO-8859-1"));//处理中文乱码

Answer 1

<tr>
<td>用户名：</td>
<td><input type="text" name="pass" /></td>
</tr>

String name=request.getParameter("name");

写错了
你没有用户名这项

还有处理中文最好用GBK或者UTF-8比较安全 字符的处理要放在接受数据之前。。。如果还有问题 就要看最新的报错提示了

Answer 2

页面中table中写错了，两个输入框中的name都是"pass"
而你在<% %>中写的是
4: String name=request.getParameter("name");
5: String pass=request.getParameter("pass");

<tr>
<td>用户名：</td>
<td><input type="text" name="pass" /></td>
</tr>
<td>密 码：</td>
<td><input type="password" name="pass" /></td>
</tr>

手误了吧！

Answer 3

<td>用户名：</td>
<td><input type="text" name="pass" /></td>
改成<td><input type="text" name="name" /></td>即可

Answer 4

你判断的时候应该有问题应该是
if(name!=null && pass!=null &&!name.trim().equals("")&& !pass.trim().equals(""))
{

}
你试试！