数学题初二提公因式法
1.y(x+2)^2+y^2(x+2)2.x(b+c+d)-y(b+c-a)-(a-b-c)3.x^2n+3-x^2n+2+2x^2n+14.(x-y)^2n+1+2(y...
1. y(x+2)^2+y^2(x+2)
2. x(b+c+d)-y(b+c-a)-(a-b-c)
3. x^2n+3-x^2n+2+2x^2n+1
4. (x-y)^2n+1+2(y-x)^2n(y-z)-(x-z)(x-z)(x-y)^2n 展开
2. x(b+c+d)-y(b+c-a)-(a-b-c)
3. x^2n+3-x^2n+2+2x^2n+1
4. (x-y)^2n+1+2(y-x)^2n(y-z)-(x-z)(x-z)(x-y)^2n 展开
1个回答
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1. y(x+2)^2+y^2(x+2)
=y(x+2)(x+2+y)
2. x(b+c+a)-y(b+c-a)-(a-b-c) d应该是a吧???
=xb+xc+xa-yb-yc+ya-a+b+c
=b(x-y+1)+c(x-y+1)+a(x+y+1)
=(x-y+1)(b+c)+a(x+y+1)
3 x^2n+3-x^2n+2+2x^2n+1
=6+2x^2n
=2(3+x^2n)
4. (x-y)^2n+1+2(y-x)^2n(y-z)-(x-z)(x-z)(x-y)^2n
=(x-y)^2n[1+2(y-z)-(x-z)^2]+1
感觉你的3 4题有问题
=y(x+2)(x+2+y)
2. x(b+c+a)-y(b+c-a)-(a-b-c) d应该是a吧???
=xb+xc+xa-yb-yc+ya-a+b+c
=b(x-y+1)+c(x-y+1)+a(x+y+1)
=(x-y+1)(b+c)+a(x+y+1)
3 x^2n+3-x^2n+2+2x^2n+1
=6+2x^2n
=2(3+x^2n)
4. (x-y)^2n+1+2(y-x)^2n(y-z)-(x-z)(x-z)(x-y)^2n
=(x-y)^2n[1+2(y-z)-(x-z)^2]+1
感觉你的3 4题有问题
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