
2个回答
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x+y=4
x-y=2√3
xy=2²-(√3)²=1
(x+y)/(x-y)-(x-y)/(x+y)
=[(x+y)²-(x-y)²]/(x+y)(x-y)
=4xy/(x+y)(x-y)
=4/(4×2√3)
=√3/6
1/x²+1/y²
=(x²+y²)/x²y²
=[(x+y)²-2xy]/(xy)²
=(4²-2)/1²
=14
你两个括号中间是什么符号
如果是乘号
则原式=√3/6×14=7√3/3
x-y=2√3
xy=2²-(√3)²=1
(x+y)/(x-y)-(x-y)/(x+y)
=[(x+y)²-(x-y)²]/(x+y)(x-y)
=4xy/(x+y)(x-y)
=4/(4×2√3)
=√3/6
1/x²+1/y²
=(x²+y²)/x²y²
=[(x+y)²-2xy]/(xy)²
=(4²-2)/1²
=14
你两个括号中间是什么符号
如果是乘号
则原式=√3/6×14=7√3/3
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