Question

已知根号次数16-X²-根号下6-X²=2，求根号下16-X+根号下6-X²的值

呃...打错了、是“根号下16-X²”

Answer 1

(根号下16-X²-根号下6-X²)*(根号下16-X+根号下6-X²)
=(16-x^2)-(6-x^2)
=10
根号下16-X+根号下6-X²=10/(根号下16-X²-根号下6-X²)=5

Answer 2

记已知式子为A，所求式子为B，B的值为m，则A*B=（16-x^2)-(6-X
^2)=2m,所以m=5