Question

求不等式解集

4x^2-20x<25
要过程

Answer 1

4x²-20x+25<50
(2x-5)²<(±5√2)²
所以-5√2<2x-5<5√2
-5√2+5<2x<5√2+5
(-5√2+5)/2<x<(5√2+5)/2

Answer 2

相除则指数相减
所以原式=(-15/25)a^[1/2-(-1/2)]b^(1/3-1/3)c^(-3/4-5/4)
=(-3/5)a^1*b^0*c^(-2)
=-3a/(5c²)
(2x-5)²-(x-2)²=0
(2x-5+x-2)(2x-5-x+2))=0
(3x-7)(x-3)=0
x=7/3,x=3