Question

分解因式(高分送)

要过程,
(x+1)(x-1)(x^2-x+1)(x^2+x+1)
xy-1+x-y;
x^2-(a+4)+4a
2x^2+xy-y^2-4x+5y-6
8x^3+4x^2-2x-1
4xy+1-4x^2-y^2
x^2+37x+36
(6x^2-7x)2^-25

Answer 1

①(x+1)(x-1)(x^2-x+1)(x^2+x+1)
本身在实数范围内已经是分解好了，除非在复数范围内分解。
②xy-1+x-y=（x-1)(y+1)
③x^2-(a+4)+4a估计题目应该是：x²-(x+4)+4x
=x²+3x-4=(x+4)(x-1)
④2x^2+xy-y^2-4x+5y-6
=(2x-y)(x+y)-4x+5y-6
=(2x-y+2)(x+y-3)
⑤8x^3+4x^2-2x-1
=(8x³-1)+(4x²-2x)
=(2x-1)(4x²+2x+1)+2x(2x-1)
=(2x-1)(4x²+2x+2x+1)
=(2x-1)(2x+1)²
⑥4xy+1-4x^2-y^2
=1-(-4xy+4x^2+y^2)
=1-(2x-y)²
=(1+2x-y)(1-2x+y)
⑦x^2+37x+36
=(x+1)(x+36)
⑧题目应该是(6x²-7x)²-25
=（6x²-7x+5)(6x²-7x-5)
=(6x²-7x+5)(3x-5)(2x+1)

Answer 2

这么简单的题你如果不会，我没话说了。。。