Question

解不等式组，

x + (x+1) [ (x+1) - 1 ] ≤ 1

希望老师写出过程哦，谢谢谢谢啦

Answer 1

x + (x+1) [ (x+1) - 1 ] ≤ 1
把x + (x+1)看为整体
提出(x+1) 得
(x+1) （x-1）≤1
x²-1≤1
x²≤2
-根号2≤x≤根号2

Answer 2

x+(x+1)²-(x+1)<=1
x²+2x<=1
x²+2x+1<=2
(x+1)²<=2
-√2<=x+1<=√2
-1-√2<=x<=-1+√2