Question

{[(x根号x)+(x根号y)]/(xy-y2)}-[x+(根号xy)+y]/[(x根号x)-(y根号y)] y2是指y的平方；求上述式子的值。

{[(x根号x)+(x根号y)]/(xy-y2)}-[x+(根号xy)+y]/[(x根号x)-(y根号y)] 化简或计算。在线等 谢谢

Answer 1

{[(x根号x)+(x根号y)]/(xy-y2)

=[x(根号x+根号y)]/[y(x-y)]

=x/[y(根号x-根号y)]

[x+(根号xy)+y]/[(x根号x)-(y根号y)]

=[x+(根号xy)+y]/[(根号x-根号y)(x+根号xy+y)]

=1/（根号x-根号y）

{[(x根号x)+(x根号y)]/(xy-y2)}-[x+(根号xy)+y]/[(x根号x)-(y根号y)]

=x/[y(根号x-根号y)]-1/（根号x-根号y）

=(x-y)/[y(根号x-根号y)]

=(根号x+根号y)/y

Answer 2

原式
=x(√x+√y)/[y(√x-√y)(√x+√y)]-[(√x)²+√xy+(√y)²)]/[(√x)³-(√y)³]
=x/[y(√x-√y)]-1/(√x-√y)
=(x-y)/[y(√x-√y)]
=(√x+√y)/y