Question

第11题，急求，好评

Answer 1

1, DC=AC

∠DCB=∠DCA+∠ACB=60+∠ACB

∠ACE=∠ECB+∠ACB=60+∠ACB

∠DCB=∠ACE

BC=EC

△DCB≌△ACE

AE=BE

2, 设AC,DB交于F点，BC,AE交于G点  

△DCB≌△ACE  

∠CDF=∠MAF ∠DFC=∠AFM

△DFC∽△AFM

CF/MF=DF/AF  ∠DFC=∠AFM

△CFM∽△DFA

∠CMF=∠DAF=60

即∠CMD=60 

同理可证∠CME=60

故：MC平分∠DME

Answer 2

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