Question

LISP怎么去除一个字符串中的罗马数字

LISP怎么去除一个字符串中的罗马数字，比如字符串“A4B5CD”,去除罗马数字4和5，变为"ABCD"。

Answer 1

用find的替换功能

查找对象请输入[0-9]

替换成空即可

lisp的话，用vl-string-subst函数，下面是函数说明：

vl-string-subst

Substitutes one string for another, within a
string
(vl-string-subst new-str pattern string [start-pos])

Arguments

new-str

The string to be substituted for pattern.

pattern

A string containing the pattern to be replaced.

string

The string to be searched for pattern.

start-pos

An integer identifying the starting position of the search;
0 if omitted.

Note that the search is case-sensitive, and that vl-string-subst substitutes only the first
occurrence it finds of the string.

Return Values

The value of string after any
substitutions have been made.

追问

不太清楚