Question

关于使用Springmvc的MultipartHttpServletRequest来获得表单上传文件的问题，万分感谢~

环境：tomcat7， ssh， eclipse
具体情况：表单上的enctype已经设置为multipart/form-data, method="post", 在applicationContext.xml文件上已经加上<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver"></bean>
表单是既有type为file的input标签，也有type为text的input标签（我是想文件和数据一起提交）；
其中代码：multipartRequest = (MultipartHttpServletRequest) baseRequest; 这个刚开始报类型转换错误，后来使用
CommonsMultipartResolver commonsMultipartResolver = new CommonsMultipartResolver(baseRequest
.getSession().getServletContext());
commonsMultipartResolver.setDefaultEncoding("utf-8");
multipartRequest = commonsMultipartResolver.resolveMultipart(baseRequest);
终于获得multipartRequest对象， 但是multipartRequest.getfile(...)和multipartRequest.getParameter(...)都是null，取不了任何东西，到底如何破啊？已困扰多时，万分感谢啦！

Answer 1

try {
//下面这句必须加，不然报错
MultipartResolver resolver = new CommonsMultipartResolver(request.getSession().getServletContext());
MultipartHttpServletRequest multipartRequest = (MultipartHttpServletRequest) request;
//获取一起跟文件传过来的其他参数值
String id = multipartRequest.getParameter("id");
//获取上传上来的文件
Map<String, MultipartFile> fileMap = multipartRequest.getFileMap();
for (Map.Entry<String, MultipartFile> entry : fileMap.entrySet()){
MultipartFile file = entry.getValue();
String fileName = file.getOriginalFilename();
System.out.println(fileName);
String path = "C:\\Users\\Administrator\\Desktop" + File.separator + fileName;
file.transferTo(new File(path));
}

} catch (Exception e) {
e.printStackTrace();
}

Answer 2

直接在Controller用@RequestParam MultipartFile[] 变量名 接收文件不就行了么，input的name与Controller中的参数名一样

Answer 3

request.getFileMap(),然后遍历获取文件，参数用request.getParameterNames,然后循环遍历

Answer 4

那这个type为file的input的标签有name属性吗