Question

用数组方法求1,3,3,3,5,5,5,5,5,7,7,7,7,7,7,7……的第四十项

Answer 1

用数组方法求1,3,3,3,5,5,5,5,5,7,7,7,7,7,7,7……的第四十项
1+3+5+7+9+11=36
所以1,3,3,3,5,5,5,5,5,7,7,7,7,7,7,7……的第四十项是13

Answer 2

#include <stdio.h>
#define N 40
int main(void) {
int i = 0, j = 1, k, a[N];
while (i < N) {
for (k = 0; k < j; k++) {
a[i] = j;
if (i++ >= N) break;
}
j += 2;
}
printf("%d\n", a[N - 1]);
return 0;
}