Question

从键盘上输入十个整数，并求出这十个数所有奇数之和及偶数之和。C++编程，要求有do while，w

从键盘上输入十个整数，并求出这十个数所有奇数之和及偶数之和。C++编程，要求有do while，while和for三种循环结构实现。

Answer 1

#include<iostream>
using namespace std;

int main()
{
    int a[10],EvenTotal=0,OddTotal=0;
    cout<<"请输入10个整数"<<endl;
    for(int i=0;i<10;i++)
        cin>>a[i];
    int j=0;
    while(j<10) //while循环
    {
        if(a[j]%2==0)
            EvenTotal+=a[j];
        else
            OddTotal+=a[j];
        j++;
    }
    cout<<"偶数和:"<<EvenTotal<<endl;
    cout<<"奇数和:"<<OddTotal<<endl;
    return 0;
}


#include<iostream>
using namespace std;


int main()
{
    int a[10],EvenTotal=0,OddTotal=0;
    cout<<"请输入10个整数"<<endl;
    for(int i=0;i<10;i++)
        cin>>a[i];
    int j=0;
    do //do-while循环
    {
        if(a[j]%2==0)
            EvenTotal+=a[j];
        else
            OddTotal+=a[j];
        j++;
    }while(j<10);
    cout<<"偶数和:"<<EvenTotal<<endl;
    cout<<"奇数和:"<<OddTotal<<endl;
    return 0;
}



#include<iostream>
using namespace std;

int main()
{
    int a[10],EvenTotal=0,OddTotal=0;
    cout<<"请输入10个整数"<<endl;
    for(int i=0;i<10;i++)
        cin>>a[i];
    for(int j=0;j<10;j++) //for循环
    {
        if(a[j]%2==0)
            EvenTotal+=a[j];
        else
            OddTotal+=a[j];
    }
    cout<<"偶数和:"<<EvenTotal<<endl;
    cout<<"奇数和:"<<OddTotal<<endl;
    return 0;
}

运行结果：

Answer 2

#include<stdio.h>

int main()
{
    int i;
    int num;
    int jishu,oushu;
    
    /* do while */
    i=0;
    jishu=oushu=0;
    do
    {
        scanf("%d",&num);
        if(num%2==0)
        {
            oushu+=num;
        }
        else
        {
            jishu+=num;
        }
        i++;
    }while(i<10);
    printf("jishu=%d,oushu=%d\n",jishu,oushu);
    
    /* while */
    i=0;
    jishu=oushu=0;
    while(i<10)
    {
        scanf("%d",&num);
        if(num%2==0)
        {
            oushu+=num;
        }
        else
        {
            jishu+=num;
        }
        i++;
    }
    printf("jishu=%d,oushu=%d\n",jishu,oushu);
    
    /* for */
    jishu=oushu=0;
    for(i=0;i<10;i++)
    {
        scanf("%d",&num);
        if(num%2==0)
        {
            oushu+=num;
        }
        else
        {
            jishu+=num;
        }
    }
    printf("jishu=%d,oushu=%d\n",jishu,oushu);
    
    return 0;
}

追问

谢谢

Answer 3

很简单，采纳就给你写