1个回答
2015-05-27
展开全部
4n²-2mn/4n²-m² + m²+2mn/4n²-m² + 4mn/4n²-m²
= 4n²-2mn+m²+2mn+4mn/4n²-m²
=(2n)²+m²+4mn/4n²-m²
=(2n+m)²/(2n+m)(2n-m)
=2n+m/2n-m
= 4n²-2mn+m²+2mn+4mn/4n²-m²
=(2n)²+m²+4mn/4n²-m²
=(2n+m)²/(2n+m)(2n-m)
=2n+m/2n-m
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