
求学霸帮忙16题分解因式
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2016-04-21 · 知道合伙人教育行家
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16。因式分解:
(1) 16x^2-1=(4x+1)(4x-1).
(2) 8ab^3c^2-32a^2b^2c+ab^2c
=ab^2c(8bc-32a+1).
(3) 2m^2--8n^2=2(m^2-4n^2)
=2(m+2n)(m-2n).
(4) 4(a-y)+25x^2(y-a)
=(a-y)(4-25x^2
=(a-y)(2+5x)(2-5x).
(5) 4q(1-p)^3+2(p-1)^2
=2(1-p)^2[ 2q(1-p) -1]
=2(1-p)^2(2q-2pq-1).
(6) x^2-2xy+y^2+2x-2y-3
=(x-y)^2+2(x-y)-3
=[(x-y)+3][(x-y)-1]
=(x-y+3)(x-y+1).
(1) 16x^2-1=(4x+1)(4x-1).
(2) 8ab^3c^2-32a^2b^2c+ab^2c
=ab^2c(8bc-32a+1).
(3) 2m^2--8n^2=2(m^2-4n^2)
=2(m+2n)(m-2n).
(4) 4(a-y)+25x^2(y-a)
=(a-y)(4-25x^2
=(a-y)(2+5x)(2-5x).
(5) 4q(1-p)^3+2(p-1)^2
=2(1-p)^2[ 2q(1-p) -1]
=2(1-p)^2(2q-2pq-1).
(6) x^2-2xy+y^2+2x-2y-3
=(x-y)^2+2(x-y)-3
=[(x-y)+3][(x-y)-1]
=(x-y+3)(x-y+1).
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(1)原式=(4x+1)(4x-1)
(2)原式=ab^2c(8bc-32a+1)
(3)原式=2(m^2-4n^2)
=2(m+2n)(m-2n)
(4)原式=(a-y)(4-25x^2)
=(a-y)(2+5x)(2-5x)
(5)原式=2(1-p)^2*(2q-2qp+1)
(6)原式=(x-y)^2+2(x-y)-3
=(x-y+3)(x-y-1)
(2)原式=ab^2c(8bc-32a+1)
(3)原式=2(m^2-4n^2)
=2(m+2n)(m-2n)
(4)原式=(a-y)(4-25x^2)
=(a-y)(2+5x)(2-5x)
(5)原式=2(1-p)^2*(2q-2qp+1)
(6)原式=(x-y)^2+2(x-y)-3
=(x-y+3)(x-y-1)
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