
1个回答
展开全部
10(1) 第 1 行 -1 倍加到第 2 行, 第 3 行 -1 倍加到第 4 行,得 D =
|1 1 2 3|
|0 1-x^2 0 0|
|2 3 1 5|
|0 0 0 4-x^2|
D = (4-x^2)*
|1 1 2|
|0 1-x^2 0|
|2 3 1|
D = (4-x^2)(1-x^2)*
|1 2|
|2 1|
D = -3(4-x^2)(1-x^2) = 0,
x = ±2, ±1
|1 1 2 3|
|0 1-x^2 0 0|
|2 3 1 5|
|0 0 0 4-x^2|
D = (4-x^2)*
|1 1 2|
|0 1-x^2 0|
|2 3 1|
D = (4-x^2)(1-x^2)*
|1 2|
|2 1|
D = -3(4-x^2)(1-x^2) = 0,
x = ±2, ±1
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询