react中怎么获取鼠标点击位置到div边界的距离
<HEAD>
<TITLE> JS获取DIV相对坐标</TITLE>
<mce:script type="text/javascript"><!--
function getX(obj){
var parObj=obj;
var left=obj.offsetLeft;
while(parObj=parObj.offsetParent){
left+=parObj.offsetLeft;
}
return left;
}
function getY(obj){
var parObj=obj;
var top=obj.offsetTop;
while(parObj = parObj.offsetParent){
top+=parObj.offsetTop;
}
return top;
}
function DisplayCoord(event){
var top,left,oDiv;
oDiv=document.getElementById("demo");
top=getY(oDiv);
left=getX(oDiv);
document.getElementById("mp_x").innerHTML = (event.clientX-left+document.body.scrollLeft) -2+"px";
document.getElementById("mp_y").innerHTML = (event.clientY-top+document.body.scrollTop) -2+"px";
}
// --></mce:script>
</HEAD>
<BODY style="margin:40px;" mce_style="margin:40px;">
<div style="background-color:#000000;color:#0011FF;width:300px;height:300px;
position:absolute;top:80px;left:90px;margin:0px; border:0px;"
id="demo" onmousemove="DisplayCoord(event)">
我是DIV,经测试,有2PX的误差...
</div>
当前鼠标坐标为：
X：<span id="mp_x"></span>
Y：<span id="mp_y"></span>
</body>
</BODY>
</HTML>
