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(7)
y=√[(x-1)/(x+1)]
lny = (1/2)[ ln(x-1) - ln(x+1) ]
(1/y)y' = (1/2)[ 1/(x-1) - 1/(x+1) ]
y' =(1/2)[ 1/(x-1) - 1/(x+1) ] .√[(x-1)/(x+1)]
={ 1/[(x-1)(x+1)] } .√[(x-1)/(x+1)]
=(x-1)^(-1/2) . (x+1)^(-3/2)
y=√[(x-1)/(x+1)]
lny = (1/2)[ ln(x-1) - ln(x+1) ]
(1/y)y' = (1/2)[ 1/(x-1) - 1/(x+1) ]
y' =(1/2)[ 1/(x-1) - 1/(x+1) ] .√[(x-1)/(x+1)]
={ 1/[(x-1)(x+1)] } .√[(x-1)/(x+1)]
=(x-1)^(-1/2) . (x+1)^(-3/2)
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