因式分解2x^4-x^3+6x^2-x-6
1个回答
展开全部
2x4-x3-6x2-x+2
=x^2(2x^2-x-6)-(x-2)
=x^2(2x+3)(x-2)-(x-2)
=(x-2)[x^2(2x+3)-1]
=(x-2)(2x^3+3x^2-1)
=(x-2)[(2x^3+2x^2)+(x^2-1)]
=(x-2)[2x^2(x+1)+(x+1)(x-1)]
=(x-2)(x+1)(2x^2+x-1)
=(x-2)(x+1)(2x-1)(x+1)
=(x+1)^2(x-2)(2x-1)
=x^2(2x^2-x-6)-(x-2)
=x^2(2x+3)(x-2)-(x-2)
=(x-2)[x^2(2x+3)-1]
=(x-2)(2x^3+3x^2-1)
=(x-2)[(2x^3+2x^2)+(x^2-1)]
=(x-2)[2x^2(x+1)+(x+1)(x-1)]
=(x-2)(x+1)(2x^2+x-1)
=(x-2)(x+1)(2x-1)(x+1)
=(x+1)^2(x-2)(2x-1)
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
