Question

2kπ≤6x+12/π≤π+2kπ化简？

Answer 1

2kπ≤6x+12/π≤π+2kπ
即：2kπ-12/π≤6x≤（2k+1）π-12/π
∴ kπ/3-2/π≤x≤（2k+1）π/6-2/π

Answer 2

2kπ≤6x+(π/12)≤2kπ+π
==》 2kπ-(π/12)≤6x≤2kπ+π-(π/12)
==》 2kπ-(π/12)≤6x≤2kπ+(11π/12)
==》(kπ/3)-(π/72)≤x≤(kπ/3)+(11π/72)（k∈Z）