Question

y=(2的x次方+1）/（2的x次方-1）求其反函数,

Answer 1

y=(2^x+1)/(2^x-1) (2^x-1)y=2^x+1 2^x*y-y=2^x+1 2^x(y-1)=y+1 2^x=(y+1)/(y-1) x=log以2为底(y+1)/(y-1)的对数