Question

已知m等于根号5+2.m等于2减根号5则m2020n2019的值是多少？

Answer 1

m=√5+2，n=√5-2，
mn=(√5+2)(√5-2)=1，
故原式=(mn)^2019xm
=m
=√5+2。

Answer 2

m = (√5)+2
n = 2 - （√5)
mn = (2+√5)(2-√5) = 4-5 = -1
(m^2020) * (n^2019) = m*(^2019)*(n^2019)
= m * [(mn)^2019] = m*(-1)^2019 = -m = -2-√5