Question

已知a²+ab=3,ab+b²=1,求a²+2ab+b²和a²-b²的值.请您说出计算过程和方法。

谢谢

Answer 1

a²+2ab+b²
= a²+ab + ab+b²
= 3 +1
= 4

a²-b²
= (a²+ab)-(ab+b²)
= 3 -1
= 2