(a-b分之a+b)的平方*3a+3b分之2a-2b-a方-b方分之a方/b分之a 怎么做
2个回答
2013-12-12
展开全部
原式=(a+b)�0�5/(a-b)�0�5×2(a-b)/3(a+b)-a�0�5/(a+b)(a-b)×b/a
=2(a+b)/3(a-b)-ab/(a+b)(a-b)
=(2a�0�5+4ab+2b�0�5-3ab)/3(a+b)(a-b)
=(2a�0�5+ab+2b�0�5)/(3a�0�5-3b�0�5)
=2(a+b)/3(a-b)-ab/(a+b)(a-b)
=(2a�0�5+4ab+2b�0�5-3ab)/3(a+b)(a-b)
=(2a�0�5+ab+2b�0�5)/(3a�0�5-3b�0�5)
2013-12-12
展开全部
[(a+b)/(a-b)]^2[(2a-2b)/(3a+3b)]-[a^2/(a^2-b^2)]/(a/b)
=2(a-b)(a+b)^2/[3(a+b)(a-b)^2]-a^2b/[a(a^2-b^2)]
=2(a+b)^2/[3(a+b)(a-b)]-3ab/[3(a+b)(a-b)]
=(2a^2+2b^2+4ab-3ab)/[3(a+b)(a-b)]
=(2a^2-ab+2b^2)/[3(a+b)(a-b)]
=2(a-b)(a+b)^2/[3(a+b)(a-b)^2]-a^2b/[a(a^2-b^2)]
=2(a+b)^2/[3(a+b)(a-b)]-3ab/[3(a+b)(a-b)]
=(2a^2+2b^2+4ab-3ab)/[3(a+b)(a-b)]
=(2a^2-ab+2b^2)/[3(a+b)(a-b)]
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