先化简再求值:(x-1分之x的平方-x+1)除以1-x分之4x的平方-4x+1,其中x满足x的平方+x-2=0
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x²+x-2=0
(x-1)(x+2)=0x=1或x=-2(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=(x²-x+1)/(x-1)*(1-x)/(4x²-4x+1)=-(x²-x+1)/(4x²-4x+1)=-(x²-x+1)/(2x-1)²当x=1时(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=-(x²-x+1)/(2x-1)²=-1/1=-1当x=-2时(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=-(x²-x+1)/(2x-1)²=-7/25
(x-1)(x+2)=0x=1或x=-2(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=(x²-x+1)/(x-1)*(1-x)/(4x²-4x+1)=-(x²-x+1)/(4x²-4x+1)=-(x²-x+1)/(2x-1)²当x=1时(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=-(x²-x+1)/(2x-1)²=-1/1=-1当x=-2时(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=-(x²-x+1)/(2x-1)²=-7/25
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