！！初一数学，要过程，请大神解答！谢谢！
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（1）改雀原式=2a/[a+2)(a-2)]-1/(a-2)
=[2a-(a+2)]/[(a+2)(a-2)]
=(2a-a-2)/[(a+2)(a-2)]
=(a-2)/[(a+2)(a-2)]
=1/(a+2)
(2)原式={1/(x+1)-(x+3)/[(x+1)(x-1)]}×(x-1)
={[(x-1)-(x+3)]/[(x+1)(x-1)]}×(x-1)
=(x-1-x-3)×(x-1)/[(x+1)(x-1)]
=-4/(x+1)
四、两边竖轮同乘以2（核纤早x-1)
3-2=6(x-1)
6x-6=1
x=7/6
=[2a-(a+2)]/[(a+2)(a-2)]
=(2a-a-2)/[(a+2)(a-2)]
=(a-2)/[(a+2)(a-2)]
=1/(a+2)
(2)原式={1/(x+1)-(x+3)/[(x+1)(x-1)]}×(x-1)
={[(x-1)-(x+3)]/[(x+1)(x-1)]}×(x-1)
=(x-1-x-3)×(x-1)/[(x+1)(x-1)]
=-4/(x+1)
四、两边竖轮同乘以2（核纤早x-1)
3-2=6(x-1)
6x-6=1
x=7/6
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