Question

可不可以帮我写一个8*8点阵显示0~9数字循环的C语言程序，要求每隔1s换一个数字，拜托拜托

Answer 1

#include<stdio.h>
#include<stdlib.h>
#include<windows.h>
void PrintNum(int n)
{
	switch(n)
	{
		case 0:
			printf("********\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("********\n");
			break;
		case 1:
			printf("  ***   \n");
			printf("    *   \n");
			printf("    *   \n");
			printf("    *   \n");
			printf("    *   \n");
			printf("    *   \n");
			printf("    *   \n");
			printf("  ***** \n");
			break;
		case 2:	
			printf("********\n");
			printf("       *\n");
			printf("       *\n");
			printf("********\n");
			printf("*       \n");
			printf("*       \n");
			printf("*       \n");
			printf("********\n");
			break;
		case 3:	
			printf("********\n");
			printf("       *\n");
			printf("       *\n");
			printf("********\n");
			printf("       *\n");
			printf("       *\n");
			printf("       *\n");
			printf("********\n");
			break;
		case 4:	
			printf("      **\n");
			printf("     * *\n");
			printf("    *  *\n");
			printf("   *   *\n");
			printf("  *    *\n");
			printf("********\n");
			printf("       *\n");
			printf("       *\n");
			break;
		case 5:	
			printf("********\n");
			printf("*       \n");
			printf("*       \n");
			printf("********\n");
			printf("       *\n");
			printf("       *\n");
			printf("       *\n");
			printf("********\n");
			break;
		case 6:	
			printf("********\n");
			printf("*       \n");
			printf("*       \n");
			printf("********\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("********\n");
			break;
		case 7:	
			printf("********\n");
			printf("       *\n");
			printf("       *\n");
			printf("       *\n");
			printf("       *\n");
			printf("       *\n");
			printf("       *\n");
			printf("       *\n");
			break;
		case 8:	
			printf("********\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("********\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("********\n");
			break;
		case 9:	
			printf("********\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("*      *\n");
			printf("********\n");
			printf("       *\n");
			printf("       *\n");
			printf("********\n");
			break;
			
	}
} 
int main()
{	
int i = 0;
while(1)
{
	system("cls");
	PrintNum(i);
	i++;
	if(i==10)i=0;
	Sleep(1000);
}
	
return 0;
}

Answer 2

就打印字符的问题，sleep一秒打一张不就行啦

追问

不懂啊，我需要的是C语言程序

追答