谁能帮我一下?
1个回答
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(1)
1/(2a),1/(3b)
1/(2a)=(3b)/(6ab)
1/(3b)=(2a)/(6ab)
(2)
x/(x-y),2/(x-2)
x/(x-y)=(x²-2x)/(x²-2x-xy+2y)
2/(x-2)=(2x-2y)/(x²-2x-xy+2y)
(3)
1/(a-b),1/(a²-b²)
1/(a-b)=(a+b)/(a²-b²)
1/(a²-b²)=1/(a²-b²)
(4)
x²/(x-y)+y²/(y-x)
=x²/(x-y)-y²/(x-y)
=(x²-y²)/(x-y)
=x+y
1/(2a),1/(3b)
1/(2a)=(3b)/(6ab)
1/(3b)=(2a)/(6ab)
(2)
x/(x-y),2/(x-2)
x/(x-y)=(x²-2x)/(x²-2x-xy+2y)
2/(x-2)=(2x-2y)/(x²-2x-xy+2y)
(3)
1/(a-b),1/(a²-b²)
1/(a-b)=(a+b)/(a²-b²)
1/(a²-b²)=1/(a²-b²)
(4)
x²/(x-y)+y²/(y-x)
=x²/(x-y)-y²/(x-y)
=(x²-y²)/(x-y)
=x+y
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