Question

shell 获取xml中ip并赋值

<ipConfig version="R8" softwareNo="ip" version="100">
<Interface rec_num="1">
<Row intf="eth0" netmask="255.255.255.0" ip="10.16.10.222"/>
<Row intf="eth1" netmask="255.255.255.0" ip="10.16.11.223"/>
</Interface>
想从里面获得eth0的ip值并赋值给变量find_ip
#!/bin/bash
find_ip=$(sed -nr '/row ip/{s/.*<row ip="([^"]+)".*/\1/;p}' ip.xml)
echo $find_ip
我是这么写的，但读不到Ip是为什么呢？

Answer 1

#!/bin/bash

find_ip=$(sed -nr 's/.*eth0.*ip="(.*)".*/\1/p' ip.xml)

echo $find_ip

Answer 2

sed -nr '/Row .*ip/{s/.*<Row.* ip="([^"]+)".*/\1/;p}' ip.xml