Question

用因式分解法帮我解一下

Answer 1

(1)5 X²—5X=3X²+3X

2X²—8X=0

2X(X—4)=0

X₁=0， X₂=4

(2) X²—5X+6=12

X²—5X—6=0

(X—6)(X+1) =0

X₁=6， X₂=—1

(3)2Y²+3Y—2=0

(2Y—1)(Y+2)=0

Y₁=1/2， Y₂=—2

Answer 2

Answer 3

Answer 4

①：原题化简 5x^2-5x-3x^2-3x=2x^2-8x=2x(x-4）=0， 解得x=0或4；
②：原题化简 x^2-3x-2x+6-12=x^2-5x-6=(x+1)(x-6)=0,解得x=-1或6；
③：原题化简 2y^2+3y-2=（2y-1)(y+2)=0,解得x=1/2或-2

Answer 5

(1)、5(x^2-x)=3(x^2+x)
5x^2-5x=3x^2+3x
2x^2-8x=0
x(x-4)=0
解得x=0或者x=4
(3)、(x-2)(x-3)=12
x^2-5x+6=12
x^2-5x-6=0
(x-6)(x+1)=0
解得x=6或x=-1
(5)、2y^2+4y=y+2
移项，得
2y^2+3y-2=0
(2y-1)(y+2)=0
解得y=1/2或y=-2