Question

lingo建模语言，如何表达：当i=1,3,5,6,9时：x(i)<x(i+1)

Answer 1

这样就可以了，你参考下：

sets:
set1/1..10/: x;
set2/1,3,5,6,9/;
endsets

@for(set2(I): x(I) < x(I+1) );

追问

另外：
model:

title消防车调度;
sets:
f/1..7/:y,a;
z/1..3/:k;
fz(f,z):s,x;
endsets

在上面条件下,如何表达：当i=1,3,5,6,9时：x(i,j)<x(i+1,j)

追答

sets:
f1/1..10/: y, a;
z/1..3/: k;

f2/1,3,5,6,9/;
fz(f2, z): s, x;

endsets

@for(fz(I, J): x(I, J) < x(I+1, J) );