Question

java【不用list】如何将数组元素顺序打乱

String[] cards = {"A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"}
打乱顺序 不用list<>

Answer 1

public class RandomNumber {

public static void main(String[] args) {
String[] cards = { "A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K" };
for (int i = 0; i < 10; i++) {
int firstIndex = (int) (Math.random() * Math.round(cards.length));
int secondIndex = (int)(Math.random() * Math.round(cards.length));
if (firstIndex == secondIndex)
continue;
String temp = cards[firstIndex];
cards[firstIndex]=cards[secondIndex];
cards[secondIndex]=temp;
}
for(String s:cards)
System.out.println(s);
}
}

//望采纳，谢谢

Answer 2

这好办得很嘛, 假如长度为10, 从10内随机取一个数,把改下标的值和下标0互换, 换个10次或者更高就行了

追问

能贴个代码吗

追答

public static void main(String[] args) {
        String[] cards = {"A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"};
        int len = cards.length;
        java.util.Random ran = new java.util.Random();
        for(int i = 0;i < 10;i++){
            int temp = ran.nextInt(len);
            String c = cards[temp];
            cards[temp]=cards[0];
            cards[0]=c;
        }
        for(int i = 0;i < len; i++){
            System.out.print(cards[i]+" ");
        }
    }