㏒₂0.5㏒0.5(1.5) 0.3²比大小。 50
1个回答
展开全部
log0.5(1.5)=log(1/2)(1.5)=log2(1.5)/log2(1/2)=-log2(1.5)<0
log2(0.5)-log0.5(1.5)=log2(0.5)-[-log2(1.5)]=log2(0.5)+og2(1.5)=log2(0.75)<0
所以,log2(0.5)-log0.5(1.5)<0
log0.5(1.5)>log2(0.5)
又log2(0.5)=log2(1/2)=-1<0
log0.5(1.5)=-log2(1.5)<0
0.3^2=0.09>0
所以:0.3^2>log0.5(1.5)>log2(0.5)
log2(0.5)-log0.5(1.5)=log2(0.5)-[-log2(1.5)]=log2(0.5)+og2(1.5)=log2(0.75)<0
所以,log2(0.5)-log0.5(1.5)<0
log0.5(1.5)>log2(0.5)
又log2(0.5)=log2(1/2)=-1<0
log0.5(1.5)=-log2(1.5)<0
0.3^2=0.09>0
所以:0.3^2>log0.5(1.5)>log2(0.5)
本回答由网友推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
