Question

springmvc启动tomcat报错

严重: StandardWrapper.Throwable
org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from ServletContext resource [/WEB-INF/spmvc-servlet.xml]; nested exception is java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/spmvc-servlet.xml]

下面是web.xml的配置。在线求解决
<!-- springmvc 配置 -->
<servlet>
<servlet-name>spmvc</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spmvc</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation </param-name>
<param-value>/WEB-INF/classes/applicationContext.xml </param-value>
</context-param>

Answer 1

把你的wepapp下面只启动一个系统，这样要快点