Question

因式分解(P-1)(p-3)=15 (t -3)(t+1)=5

x的平方减13x减14 x的平方减2x减63 x的平方减5x加6 x的平方减5x减6

Answer 1

(P-1)(p-3)=15
p^2-4t+3-15=0
p^2-4t-12=0
(p-6)(p+2)=0
所以 p=6 或 p=-2

(t -3)(t+1)=5
t^2-2t-3-5=0
t^2-2t-8=0
(t-4)(t+2)=0
所以 t=4 或 t=-2

x^2-13x-14
(x-14)(x+1)

x^2-2x-63
(x-9)(x+7)

x^2-5x+6
(x-2)(x-3)

x^2-5x-6
(x-6)(x+1)

Answer 2

1.(P-1)(p-3)=15
P^2-4P+3=15 ==>P^2-4P-12=0 ==>(P-6)(P+2)=0==>P=6 或P=-2
2.(t -3)(t+1)=5
T^2-2T-3=5 ==>T^2-2T-8=0 ==> (T-4)(T+2)=0==> T=4或T=-2