Question

求下图中第3题的解题过程及答案

Answer 1

(3)
x-e^x.sinθ +1=0
θ=0,
x|θ=0 +1=0
x|θ=0 =-1
y-θ^3-2θ=0
θ=0
y|θ=0 = 0
x-e^x.sinθ +1=0
dx/dθ - (sinθ.dx/dθ + cosθ) =0
(1-sinθ).dx/dθ = cosθ
dx/dθ = cosθ/(1-sinθ)
y-θ^3-2θ=0
dy/dθ -3θ^2 -2=0
dy/dθ=3θ^2+2
dy/dx
= (dy/dθ)/ (dx/dθ)
= [3θ^2+2] /[cosθ/(1-sinθ)]
= [(1-sinθ).(3θ^2+2)]/cosθ
dy/dx |θ=0
= 2
切线方程 ( x|θ=0, y|θ=0) =(-1,0)
y-y|θ=0 = (dy/dx |θ=0 ).(x- x|θ=0)
y-0 = 2(x+1)

2x-y+2 =0