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(1)
x轴 =>y=0
x(1-x)=0
x=0 or 1
A
=∫(0->1) x(1-x) dx
=[ (1/2)x^2 -(1/3)x^3]|(0->1)
=1/6
(2)
Vx
=π∫(0->1) [x(1-x)]^2 dx
=π∫(0->1) (x^2-2x^3+x^4 ) dx
=π[ (1/3)x^3 - (1/2)x^4 +(1/5)x^5]|(0->1)
=π ( 1/3 -1/2 +1/5)
=π/30
x轴 =>y=0
x(1-x)=0
x=0 or 1
A
=∫(0->1) x(1-x) dx
=[ (1/2)x^2 -(1/3)x^3]|(0->1)
=1/6
(2)
Vx
=π∫(0->1) [x(1-x)]^2 dx
=π∫(0->1) (x^2-2x^3+x^4 ) dx
=π[ (1/3)x^3 - (1/2)x^4 +(1/5)x^5]|(0->1)
=π ( 1/3 -1/2 +1/5)
=π/30
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