Question

高数函数求偏导

设函数z=z（x,y）,由方程e^x+sin2y-z^2=e^z,求δz/δx和δz/δy.

Answer 1

e^x+sin2y-z^2=e^z
e^x - 2z.δz/δx = e^z.δz/δx
(e^z+2z).δz/δx =e^x
δz/δx =e^x/(e^z+2z)
/
e^x+sin2y-z^2=e^z
2cos2y- 2z.δz/δy = e^z.δz/δy
(e^z+2z).δz/δy =2cos2y
δz/δy =2cos2y/(e^z+2z)